What is the integral from 0 to x of sin(t^3+1) ?

The integral from 0 to x of sin(t^3+1) is

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integral from 0 to x of sin(t^3+1)

\int_{0}^{x} sin (t^{3} + 1) d t

Solution steps

\int_{0}^{x} sin (t^{3} + 1) d t

Rewrite using trig identities

= \int_{0}^{x} cos (t^{3}) sin (1) + cos (1) sin (t^{3}) d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{x} cos (t^{3}) sin (1) d t + \int_{0}^{x} cos (1) sin (t^{3}) d t

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What is the integral from 0 to x of sin(t^3+1) ?
The integral from 0 to x of sin(t^3+1) is