What is the integral from-2 to 6 of h(x) ?

The integral from-2 to 6 of h(x) is h*16

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integral from-2 to 6 of h(x)

\int_{- 2}^{6} h (x) d x

h \cdot 16

Solution steps

\int_{- 2}^{6} h x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= h \cdot \int_{- 2}^{6} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{- 2}^{6}

= h [\frac{x ^{2}}{2}]_{- 2}^{6}

Compute the boundaries:

16

= h \cdot 16

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What is the integral from-2 to 6 of h(x) ?
The integral from-2 to 6 of h(x) is h*16