What is the integral from 0 to pi of sin^2(t) ?

The integral from 0 to pi of sin^2(t) is pi/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to pi of sin^2(t)

\int_{0}^{π} sin^{2} (t) d t

\frac{π}{2}

Decimal Notation

1.57079 \dots

Solution steps

\int_{0}^{π} sin^{2} (t) d t

Rewrite using trig identities

= \int_{0}^{π} \frac{1 - cos ( 2 t )}{2} d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{0}^{π} 1 - cos (2 t) d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (\int_{0}^{π} 1 d t - \int_{0}^{π} cos (2 t) d t)

\int_{0}^{π} 1 d t = π

\int_{0}^{π} cos (2 t) d t = 0

= \frac{1}{2} (π - 0)

Simplify

\frac{1}{2} (π - 0) : \frac{π}{2}

= \frac{π}{2}

\frac{d}{d x} (\frac{4}{x - 2})

\frac{d}{d x} (ln (3 + 2 x))

x \to 1 lim (x^{2} + 1)

\int 1 + x d x

(3 x + 5)^{4} x

What is the integral from 0 to pi of sin^2(t) ?
The integral from 0 to pi of sin^2(t) is pi/2