What is the derivative of f(t)=t^2-pi^2 ?

The derivative of f(t)=t^2-pi^2 is 2t

What is the first derivative of f(t)=t^2-pi^2 ?

The first derivative of f(t)=t^2-pi^2 is 2t

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (t) = t^{2} - π^{2}

2 t

Solution steps

\frac{d}{d t} (t^{2} - π^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (t^{2}) - \frac{d}{d t} (π^{2})

\frac{d}{d t} (t^{2}) = 2 t

\frac{d}{d t} (π^{2}) = 0

= 2 t - 0

Simplify

= 2 t

x \to 0 + lim (\frac{8}{5 x ^{\frac{1}{5}}})

\frac{d}{d x} (\frac{x - x}{x ^{\frac{1}{6}}})

\frac{d x}{d t} = e^{x} sin (t)

e^{2 s i n (3 v)}

2 - 2 x

What is the derivative of f(t)=t^2-pi^2 ?
The derivative of f(t)=t^2-pi^2 is 2t
What is the first derivative of f(t)=t^2-pi^2 ?
The first derivative of f(t)=t^2-pi^2 is 2t