What is (\partial}{\partial s}(\frac{r+s)/t) ?

The answer to (\partial}{\partial s}(\frac{r+s)/t) is 1/t

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(\partial}{\partial s}(\frac{r+s)/t)

\frac{\partial}{\partial s} (\frac{r + s}{t})

\frac{1}{t}

Solution steps

\frac{\partial}{\partial s} (\frac{r + s}{t})

Treat

r, t

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{t} \frac{\partial}{\partial s} (r + s)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{t} (\frac{\partial}{\partial s} (r) + \frac{\partial}{\partial s} (s))

\frac{\partial}{\partial s} (r) = 0

\frac{\partial}{\partial s} (s) = 1

= \frac{1}{t} (0 + 1)

Simplify

= \frac{1}{t}

sin (9 ln (x))

y^{^{'}} = 3 y - 1

\frac{3 s + 3}{( s + 4 ) ^{2}}

\int \frac{1}{441 - x ^{2}} d x

\frac{d}{d x} (cos (x) + x)

What is (\partial}{\partial s}(\frac{r+s)/t) ?
The answer to (\partial}{\partial s}(\frac{r+s)/t) is 1/t