What is the derivative of-4ln(x) ?

The derivative of-4ln(x) is -4/x

What is the first derivative of-4ln(x) ?

The first derivative of-4ln(x) is -4/x

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\frac{d}{d x} (- 4 ln (x))

- \frac{4}{x}

Solution steps

\frac{d}{d x} (- 4 ln (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 4 \frac{d}{d x} (ln (x))

Apply the common derivative:

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= - 4 \cdot \frac{1}{x}

Simplify

- 4 \cdot \frac{1}{x} : - \frac{4}{x}

= - \frac{4}{x}

\frac{\partial}{\partial x} (4 + cos (0.4 x - t))

(e^{x})^{3}

(4 x^{3} + 3 x^{2} + 3 y - 1) d x + (3 x + 2 y + 1) d y = 0

x \to \infty lim (\frac{5 e ^{- 3 x} + 2}{e ^{- 5 x} + 4})

\frac{d}{d x} (2^{2 - x^{4}})