What is the tangent of f(x)= 1/(sqrt(x)),(1,1) ?

The tangent of f(x)= 1/(sqrt(x)),(1,1) is y=-1/2 x+3/2

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tangent of f(x)= 1/(sqrt(x)),(1,1)

tangent of

f (x) = \frac{1}{x}, (1, 1)

y = - \frac{1}{2} x + \frac{3}{2}

Solution steps

Find the slope of

f (x) = \frac{1}{x} : \frac{df ( x )}{d x} = - \frac{1}{2 x ^{\frac{3}{2}}}

Compute the slope of

f (x) = \frac{1}{x}

(1, 1) : m = - \frac{1}{2}

Find the line with slope m=

- \frac{1}{2}

and passing through

(1, 1) : y = - \frac{1}{2} x + \frac{3}{2}

y = - \frac{1}{2} x + \frac{3}{2}

arccos (e^{9 x})

e^{- x + 1} \cdot x - 2 \cdot e^{- x + 1}

\frac{d}{d x} (0.5 sin (2 x))

x^{2} - 4 x + 3, - x^{2} + 2 x + 3

sin (a x^{2})

What is the tangent of f(x)= 1/(sqrt(x)),(1,1) ?
The tangent of f(x)= 1/(sqrt(x)),(1,1) is y=-1/2 x+3/2