What is (\partial)/(\partial y)(4x^3-4y) ?

The answer to (\partial)/(\partial y)(4x^3-4y) is -4

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(\partial)/(\partial y)(4x^3-4y)

\frac{\partial}{\partial y} (4 x^{3} - 4 y)

- 4

Solution steps

\frac{\partial}{\partial y} (4 x^{3} - 4 y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (4 x^{3}) - \frac{\partial}{\partial y} (4 y)

\frac{\partial}{\partial y} (4 x^{3}) = 0

\frac{\partial}{\partial y} (4 y) = 4

= 0 - 4

Simplify

= - 4

\frac{d}{d x} (- \frac{k}{x ^{2}})

\int \frac{2 x + 3}{x + 1} d x

x^{3} - 8 x^{2} + 19 x - 12

\int_{5}^{10} (3 x + 3) d x

What is (\partial)/(\partial y)(4x^3-4y) ?
The answer to (\partial)/(\partial y)(4x^3-4y) is -4