What is the derivative of f(x)=ln(6)-3x^5 ?

The derivative of f(x)=ln(6)-3x^5 is -15x^4

What is the first derivative of f(x)=ln(6)-3x^5 ?

The first derivative of f(x)=ln(6)-3x^5 is -15x^4

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derivative of

f (x) = ln (6) - 3 x^{5}

- 15 x^{4}

Solution steps

\frac{d}{d x} (ln (6) - 3 x^{5})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (ln (6)) - \frac{d}{d x} (3 x^{5})

\frac{d}{d x} (ln (6)) = 0

\frac{d}{d x} (3 x^{5}) = 15 x^{4}

= 0 - 15 x^{4}

Simplify

= - 15 x^{4}

\frac{x ^{2}}{x ^{2} + 1}

x \to \infty lim (52.2 + (41.9 \cdot e^{(- 0.055 \cdot x)}))

\frac{d}{d x} (ln (x^{2} + y))

\int \frac{1}{3 cos ( x ) + 4 sin ( x )} d x

x \to - \infty lim (0 x)

What is the derivative of f(x)=ln(6)-3x^5 ?
The derivative of f(x)=ln(6)-3x^5 is -15x^4
What is the first derivative of f(x)=ln(6)-3x^5 ?
The first derivative of f(x)=ln(6)-3x^5 is -15x^4