What is the derivative of 4/(1-9x) ?

The derivative of 4/(1-9x) is (36)/((1-9x)^2)

What is the first derivative of 4/(1-9x) ?

The first derivative of 4/(1-9x) is (36)/((1-9x)^2)

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\frac{d}{d x} (\frac{4}{1 - 9 x})

\frac{36}{( 1 - 9 x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{4}{1 - 9 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (\frac{1}{1 - 9 x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 4 \frac{d}{d x} ((1 - 9 x)^{- 1})

Apply the chain rule:

- \frac{1}{( 1 - 9 x ) ^{2}} \frac{d}{d x} (1 - 9 x)

= - \frac{1}{( 1 - 9 x ) ^{2}} \frac{d}{d x} (1 - 9 x)

\frac{d}{d x} (1 - 9 x) = - 9

= 4 (- \frac{1}{( 1 - 9 x ) ^{2}} (- 9))

Simplify

4 (- \frac{1}{( 1 - 9 x ) ^{2}} (- 9)) : \frac{36}{( 1 - 9 x ) ^{2}}

= \frac{36}{( 1 - 9 x ) ^{2}}

- \frac{x}{3}

\frac{d}{d x} (- \frac{y}{x ^{2} + y ^{2}})

\int \frac{1}{e ^{x} ( 3 + e ^{- x} )} d x

\frac{d}{d x} (e^{a x} sin (b x))

x^{2} \frac{d y}{d x} = 1 - x^{2} + y^{2} - x^{2} y^{2}

What is the derivative of 4/(1-9x) ?
The derivative of 4/(1-9x) is (36)/((1-9x)^2)
What is the first derivative of 4/(1-9x) ?
The first derivative of 4/(1-9x) is (36)/((1-9x)^2)