What is the derivative of ln^2(x^2) ?

The derivative of ln^2(x^2) is (4ln(x^2))/x

What is the first derivative of ln^2(x^2) ?

The first derivative of ln^2(x^2) is (4ln(x^2))/x

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derivative of

ln^{2} (x^{2})

\frac{4 ln ( x ^{2} )}{x}

Solution steps

\frac{d}{d x} (ln^{2} (x^{2}))

Apply the chain rule:

2 ln (x^{2}) \frac{d}{d x} (ln (x^{2}))

= 2 ln (x^{2}) \frac{d}{d x} (ln (x^{2}))

\frac{d}{d x} (ln (x^{2})) = \frac{2}{x}

= 2 ln (x^{2}) \frac{2}{x}

Simplify

2 ln (x^{2}) \frac{2}{x} : \frac{4 ln ( x ^{2} )}{x}

= \frac{4 ln ( x ^{2} )}{x}

\int_{0}^{14} 2 π x (14 x - x^{2}) d x

\frac{d}{d x} (e^{x^{2} + 3})

\frac{d}{d x} (- \frac{2 x}{x ^{2} + 1})

\int \frac{1}{2 y + y ^{2}} d y

\int_{0}^{0.6} 750 x d x

What is the derivative of ln^2(x^2) ?
The derivative of ln^2(x^2) is (4ln(x^2))/x
What is the first derivative of ln^2(x^2) ?
The first derivative of ln^2(x^2) is (4ln(x^2))/x