What is the integral of (x^2+3x+7)/(sqrt(x)) ?

The integral of (x^2+3x+7)/(sqrt(x)) is 2/5 x^{5/2}+2x^{3/2}+14sqrt(x)+C

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integral of (x^2+3x+7)/(sqrt(x))

\int \frac{x ^{2} + 3 x + 7}{x} d x

\frac{2}{5} x^{\frac{5}{2}} + 2 x^{\frac{3}{2}} + 14 x + C

Solution steps

\int \frac{x ^{2} + 3 x + 7}{x} d x

Expand

\frac{x ^{2} + 3 x + 7}{x} : x^{\frac{3}{2}} + 3 x + \frac{7}{x}

= \int x^{\frac{3}{2}} + 3 x + \frac{7}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{\frac{3}{2}} d x + \int 3 x d x + \int \frac{7}{x} d x

\int x^{\frac{3}{2}} d x = \frac{2}{5} x^{\frac{5}{2}}

\int 3 x d x = 2 x^{\frac{3}{2}}

\int \frac{7}{x} d x = 14 x

= \frac{2}{5} x^{\frac{5}{2}} + 2 x^{\frac{3}{2}} + 14 x

Add a constant to the solution

= \frac{2}{5} x^{\frac{5}{2}} + 2 x^{\frac{3}{2}} + 14 x + C

y = 5 x^{2} e^{2 x}

y = 4 \cdot 5^{x}

\frac{d}{d x} (\frac{x ( x ^{2} - 1 )}{x ^{2} + 1})

x \to 0 lim (x^{2} (sin (\frac{1}{x})))

\int x^{2} 3 + 2 x - x^{2} d x

What is the integral of (x^2+3x+7)/(sqrt(x)) ?
The integral of (x^2+3x+7)/(sqrt(x)) is 2/5 x^{5/2}+2x^{3/2}+14sqrt(x)+C