What is the limit as x approaches 0+of xsin(ln(x)) ?

The limit as x approaches 0+of xsin(ln(x)) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0+of xsin(ln(x))

x \to 0 + lim (x sin (ln (x)))

0

Solution steps

x \to 0 + lim (x sin (ln (x)))

Apply the Squeeze Theorem:

0

= 0

x \to - 8 + lim (\frac{3 - 4 x}{x + 8})

x \to 0 + lim (x ln (\frac{x}{x + 1}))

x \to 2 lim (2 x^{2} + x - 4)

x \to - 2 lim (\frac{8}{x ^{2} - 4})

x \to 0 + lim (- 1 + x ln (x))

What is the limit as x approaches 0+of xsin(ln(x)) ?
The limit as x approaches 0+of xsin(ln(x)) is 0