What is the limit as x approaches-2 of 8/(x^2-4) ?

The limit as x approaches-2 of 8/(x^2-4) is diverges

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limit as x approaches-2 of 8/(x^2-4)

x \to - 2 lim (\frac{8}{x ^{2} - 4})

diverges

Solution steps

x \to - 2 lim (\frac{8}{x ^{2} - 4})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 2 + lim (\frac{8}{x ^{2} - 4}) = - \infty

x \to - 2 - lim (\frac{8}{x ^{2} - 4}) = \infty

= diverges

x \to 0 + lim (- 1 + x ln (x))

h (x) \to 0 lim ((x + h (x))^{n})

x \to 2 lim (\frac{x ^{2} + 5 x - 14}{x ^{2} - 11 x + 18})

x \to - 1 lim (4 x + 3)

x \to - 1 lim (\frac{7 x + 3}{x + 1})

What is the limit as x approaches-2 of 8/(x^2-4) ?
The limit as x approaches-2 of 8/(x^2-4) is diverges