What is the solution for y^'=5y+e^{-2x}y^{-2} ?

The solution for y^'=5y+e^{-2x}y^{-2} is y=\sqrt[3]{(-3+17c_{1}e^{17x})/(17e^{2x)}}

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y^'=5y+e^{-2x}y^{-2}

y^{^{'}} = 5 y + e^{- 2 x} y^{- 2}

Solution steps

y^{'} (x) = 5 y + e^{- 2 x} y^{- 2}

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What is the solution for y^'=5y+e^{-2x}y^{-2} ?
The solution for y^'=5y+e^{-2x}y^{-2} is y=\sqrt[3]{(-3+17c_{1}e^{17x})/(17e^{2x)}}