What is (\partial)/(\partial y)(2x^4y-3) ?

The answer to (\partial)/(\partial y)(2x^4y-3) is 2x^4

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(\partial)/(\partial y)(2x^4y-3)

\frac{\partial}{\partial y} (2 x^{4} y - 3)

2 x^{4}

Solution steps

\frac{\partial}{\partial y} (2 x^{4} y - 3)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x^{4} y) - \frac{\partial}{\partial y} (3)

\frac{\partial}{\partial y} (2 x^{4} y) = 2 x^{4}

\frac{\partial}{\partial y} (3) = 0

= 2 x^{4} - 0

Simplify

= 2 x^{4}

\int x (x - 5)^{5} d x

(4 x - 7)^{3} (8 x - 3)

x \to 0 lim (\frac{x ^{5} + 6 x}{x})

n = 0 \sum \infty (- \frac{2}{3})^{n}

\frac{\partial}{\partial t} (s^{2} + t^{2})

What is (\partial)/(\partial y)(2x^4y-3) ?
The answer to (\partial)/(\partial y)(2x^4y-3) is 2x^4