What is the derivative of x^3+3x^2-24 ?

The derivative of x^3+3x^2-24 is 3x^2+6x

What is the first derivative of x^3+3x^2-24 ?

The first derivative of x^3+3x^2-24 is 3x^2+6x

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\frac{d}{d x} (x^{3} + 3 x^{2} - 24)

3 x^{2} + 6 x

Solution steps

\frac{d}{d x} (x^{3} + 3 x^{2} - 24)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (24)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (24) = 0

= 3 x^{2} + 6 x - 0

Simplify

= 3 x^{2} + 6 x

x \to 2 lim (\frac{∣ x - 2 ∣}{x} + 6)

\int_{0}^{1} 2 π x (21 - 21 x) d x

(t - 1) cos (4 t - 4)

\frac{\partial}{\partial x} (e^{- t} \cdot cos (π x))

\frac{2}{x - 8} (10.1)

What is the derivative of x^3+3x^2-24 ?
The derivative of x^3+3x^2-24 is 3x^2+6x
What is the first derivative of x^3+3x^2-24 ?
The first derivative of x^3+3x^2-24 is 3x^2+6x