What is the derivative of ln(x^2-2) ?

The derivative of ln(x^2-2) is (2x)/(x^2-2)

What is the first derivative of ln(x^2-2) ?

The first derivative of ln(x^2-2) is (2x)/(x^2-2)

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\frac{d}{d x} (ln (x^{2} - 2))

\frac{2 x}{x ^{2} - 2}

Solution steps

\frac{d}{d x} (ln (x^{2} - 2))

Apply the chain rule:

\frac{1}{x ^{2} - 2} \frac{d}{d x} (x^{2} - 2)

= \frac{1}{x ^{2} - 2} \frac{d}{d x} (x^{2} - 2)

\frac{d}{d x} (x^{2} - 2) = 2 x

= \frac{1}{x ^{2} - 2} \cdot 2 x

Simplify

\frac{1}{x ^{2} - 2} \cdot 2 x : \frac{2 x}{x ^{2} - 2}

= \frac{2 x}{x ^{2} - 2}

\int \frac{1}{( x + 5 ) ^{2} ( x - 2 )} d x

\frac{\partial}{\partial y} (\frac{5 x y}{x - y})

f (x) = x + \frac{3}{x}

(2 x - 1) e^{x}

y = 3 x^{2} - 4 x + 1

What is the derivative of ln(x^2-2) ?
The derivative of ln(x^2-2) is (2x)/(x^2-2)
What is the first derivative of ln(x^2-2) ?
The first derivative of ln(x^2-2) is (2x)/(x^2-2)