What is the limit as x approaches 2-of ln(4-x^2) ?

The limit as x approaches 2-of ln(4-x^2) is -infinity

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limit as x approaches 2-of ln(4-x^2)

x \to 2 - lim (ln (4 - x^{2}))

- \infty

Solution steps

x \to 2 - lim (ln (4 - x^{2}))

Apply the Limit Chain Rule:

- \infty

= - \infty

x \to 0 lim (x^{2} cos (\frac{π}{x}))

x \to 0 lim (- 1 + ln (x) x)

x \to \infty lim (\frac{sin ( 3 x )}{sin ( 4 x )})

x \to \frac{π}{4} lim (7 tan^{t a n (2 x)} (x))

x \to - 1 lim (2^{1 + l n (x)})

What is the limit as x approaches 2-of ln(4-x^2) ?
The limit as x approaches 2-of ln(4-x^2) is -infinity