What is the limit as x approaches 1 of (x^2-1)^{x-1} ?

The limit as x approaches 1 of (x^2-1)^{x-1} is Does not exist

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 1 of (x^2-1)^{x-1}

x \to 1 lim ((x^{2} - 1)^{x - 1})

Does not exist

Solution steps

x \to 1 lim ((x^{2} - 1)^{x - 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim ((x^{2} - 1)^{x - 1}) = 1

x \to 1 - lim ((x^{2} - 1)^{x - 1}) =

Does not exist

= Does not exist

x \to 3 + lim (\frac{x ^{2} + 9}{x - 3})

x \to 3 lim (5 x - 9)

x \to 1 0^{- 4} lim (ln (x))

x \to 0 lim (\frac{( 5 x + 5 )}{5})

x \to 0 lim (x e^{\frac{1}{x}} - x)

What is the limit as x approaches 1 of (x^2-1)^{x-1} ?
The limit as x approaches 1 of (x^2-1)^{x-1} is Does not exist