What is the derivative of f(x)=e^{-4x} ?

The derivative of f(x)=e^{-4x} is -4e^{-4x}

What is the first derivative of f(x)=e^{-4x} ?

The first derivative of f(x)=e^{-4x} is -4e^{-4x}

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derivative of

f (x) = e^{- 4 x}

- 4 e^{- 4 x}

Solution steps

\frac{d}{d x} (e^{- 4 x})

Apply the chain rule:

e^{- 4 x} \frac{d}{d x} (- 4 x)

= e^{- 4 x} \frac{d}{d x} (- 4 x)

\frac{d}{d x} (- 4 x) = - 4

= e^{- 4 x} (- 4)

Simplify

= - 4 e^{- 4 x}

\frac{d}{d x} (\frac{14 x + 8 x ^{2}}{( 7 + 8 x ) ^{2}})

x \to - 2 lim (\frac{x}{x ^{2} + 4})

\int e^{x^{2}} \frac{x}{3} d x

n = 0 \sum \infty 2 \cdot 5^{n}

y^{^{'}} = \frac{y}{a} - 1

What is the derivative of f(x)=e^{-4x} ?
The derivative of f(x)=e^{-4x} is -4e^{-4x}
What is the first derivative of f(x)=e^{-4x} ?
The first derivative of f(x)=e^{-4x} is -4e^{-4x}