What is the sum from n=1 to infinity of 1/(n^{1/n)} ?

The sum from n=1 to infinity of 1/(n^{1/n)} is diverges

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sum from n=1 to infinity of 1/(n^{1/n)}

n = 1 \sum \infty \frac{1}{n ^{\frac{1}{n}}}

diverges

Solution steps

n = 1 \sum \infty \frac{1}{n ^{\frac{1}{n}}}

Apply Series Divergence Test:

diverges

= diverges

n = 0 \sum \infty (- 1)^{n + 2} \cdot t^{2 n} \cdot (\frac{1}{n !})

\int_{- 11}^{0} \frac{1}{25 - x} d x

\int 12 t d t

2^{(5 x)}

\frac{d}{d x} ((x - 2)^{3})

What is the sum from n=1 to infinity of 1/(n^{1/n)} ?
The sum from n=1 to infinity of 1/(n^{1/n)} is diverges