What is the limit as x approaches 0 of 2/(1+e^{1/x)} ?

The limit as x approaches 0 of 2/(1+e^{1/x)} is diverges

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limit as x approaches 0 of 2/(1+e^{1/x)}

x \to 0 lim (\frac{2}{1 + e ^{\frac{1}{x}}})

diverges

Solution steps

x \to 0 lim (\frac{2}{1 + e ^{\frac{1}{x}}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{2}{1 + e ^{\frac{1}{x}}}) = 0

x \to 0 - lim (\frac{2}{1 + e ^{\frac{1}{x}}}) = 2

= diverges

t \frac{d y}{d t} = t^{3} + 14 t^{3} y

\frac{d}{d x} (- \frac{y}{x ^{2} + y ^{2} + 1})

\frac{1 - ln ( x )}{2 x ^{2}}

x \to 1 + lim ((x - 1)^{x - 1})

\frac{1}{s ^{2} + 6 s + 10}

What is the limit as x approaches 0 of 2/(1+e^{1/x)} ?
The limit as x approaches 0 of 2/(1+e^{1/x)} is diverges