What is maclaurin (-3+18x-45x^2)(x+4) ?

The answer to maclaurin (-3+18x-45x^2)(x+4) is -12+69x-162x^2-45x^3

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maclaurin (-3+18x-45x^2)(x+4)

maclaurin

(- 3 + 18 x - 45 x^{2}) (x + 4)

- 12 + 69 x - 162 x^{2} - 45 x^{3}

Solution steps

Apply the Maclaurin Formula

= - 12 + \frac{\frac{d}{d x} ( ( - 3 + 18 x - 45 x ^{2} ) ( x + 4 ) ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( ( - 3 + 18 x - 45 x ^{2} ) ( x + 4 ) ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( ( - 3 + 18 x - 45 x ^{2} ) ( x + 4 ) ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= - 12 + \frac{69}{1 !} x + \frac{- 324}{2 !} x^{2} + \frac{- 270}{3 !} x^{3} + \frac{0}{4 !} x^{4} + \frac{0}{5 !} x^{5} + \frac{0}{6 !} x^{6} + \frac{0}{7 !} x^{7} + \frac{0}{8 !} x^{8} + \frac{0}{9 !} x^{9} + \frac{0}{10 !} x^{10}

Refine

= - 12 + 69 x - 162 x^{2} - 45 x^{3}

\int (\frac{1}{e ^{x}}) d x

\frac{\partial}{\partial x} (\frac{x + y}{y + 1})

x \to 3 lim (x + 1)

\frac{d y}{d x}, y^{4} = x^{9}

\frac{d}{d x} (e^{x^{2} + 5 x})

What is maclaurin (-3+18x-45x^2)(x+4) ?
The answer to maclaurin (-3+18x-45x^2)(x+4) is -12+69x-162x^2-45x^3