What is the integral from-infinity to 0 of 1/(3-8x) ?

The integral from-infinity to 0 of 1/(3-8x) is diverges

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integral from-infinity to 0 of 1/(3-8x)

\int_{- \infty}^{0} \frac{1}{3 - 8 x} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{1}{3 - 8 x} d x

Compute the indefinite integral:

\int \frac{1}{3 - 8 x} d x = - \frac{1}{8} ln ∣ 3 - 8 x ∣ + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{1}{3 - 8 x} d x =

diverges

= diverges

\frac{\partial}{\partial x} (tan (x + y))

\int ln (r^{2}) d r

y^{^{'}} = 5 y sin (4 x)

\int \frac{- 1}{x} d x

\frac{1}{2 s - 5}

What is the integral from-infinity to 0 of 1/(3-8x) ?
The integral from-infinity to 0 of 1/(3-8x) is diverges