What is the derivative of ln(e^{3x}) ?

The derivative of ln(e^{3x}) is 3

What is the first derivative of ln(e^{3x}) ?

The first derivative of ln(e^{3x}) is 3

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derivative of

ln (e^{3 x})

3

Solution steps

\frac{d}{d x} (ln (e^{3 x}))

Simplify

ln (e^{3 x}) : 3 x

= \frac{d}{d x} (3 x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d x}{d x}

Apply the common derivative:

\frac{d x}{d x} = 1

= 3 \cdot 1

Simplify

= 3

(t^{2} - 3)^{2}

\frac{d}{d x} (\frac{x + 3}{x - 2})

\frac{\partial}{\partial x} (x y^{3} + 2 x y)

x \to \infty lim (tan (\frac{2 x π}{1 + 8 x}))

\int \frac{1}{36 x ^{2} - 49} d x

What is the derivative of ln(e^{3x}) ?
The derivative of ln(e^{3x}) is 3
What is the first derivative of ln(e^{3x}) ?
The first derivative of ln(e^{3x}) is 3