What is the limit as x approaches infinity of tan((2xpi)/(1+8x)) ?

The limit as x approaches infinity of tan((2xpi)/(1+8x)) is 1

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limit as x approaches infinity of tan((2xpi)/(1+8x))

x \to \infty lim (tan (\frac{2 x π}{1 + 8 x}))

1

Solution steps

x \to \infty lim (tan (\frac{2 x π}{1 + 8 x}))

Apply the Limit Chain Rule:

1

= 1

\int \frac{1}{36 x ^{2} - 49} d x

\frac{d}{d x} (\frac{4 x}{( x ^{2} + 2 ) ^{2}})

\frac{\partial}{\partial z} (x^{2} + y^{2} + z^{2})

x \to 0 + lim (x^{s i n (2 x)})

y = 6 + 5 x^{2} - 2 x^{3}

What is the limit as x approaches infinity of tan((2xpi)/(1+8x)) ?
The limit as x approaches infinity of tan((2xpi)/(1+8x)) is 1