What is the slope ofintercept (-1,-2),(3,2) ?

The slope ofintercept (-1,-2),(3,2) is y=x-1

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slope ofintercept (-1,-2),(3,2)

slope intercept

(- 1, - 2), (3, 2)

y = x - 1

Solution steps

Compute the slope

(- 1, - 2), (3, 2) : m = 1

Compute the

y

intercept:

b = - 1

Construct the line equation

y = mx + b

where

m = 1

and

b = - 1

y = x - 1

ln (x + p)

\frac{d}{d y} (- 4 y)

sec (x) d y + csc (y) d x = 0

\frac{\partial}{\partial x} (ln (x^{4} + y))

y^{^{'}} = y (2 - t y)

What is the slope ofintercept (-1,-2),(3,2) ?
The slope ofintercept (-1,-2),(3,2) is y=x-1