What is the derivative of ln(x+p) ?

The derivative of ln(x+p) is 1/(x+p)

What is the first derivative of ln(x+p) ?

The first derivative of ln(x+p) is 1/(x+p)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

ln (x + p)

\frac{1}{x + p}

Solution steps

\frac{d}{d x} (ln (x + p))

Treat

p

as a constant

Apply the chain rule:

\frac{1}{x + p} \frac{d}{d x} (x + p)

= \frac{1}{x + p} \frac{d}{d x} (x + p)

\frac{d}{d x} (x + p) = 1

= \frac{1}{x + p} \cdot 1

Simplify

= \frac{1}{x + p}

\frac{d}{d y} (- 4 y)

sec (x) d y + csc (y) d x = 0

\frac{\partial}{\partial x} (ln (x^{4} + y))

y^{^{'}} = y (2 - t y)

\frac{\partial}{\partial x} (2 x y^{2} z - 4 x z^{2})

What is the derivative of ln(x+p) ?
The derivative of ln(x+p) is 1/(x+p)
What is the first derivative of ln(x+p) ?
The first derivative of ln(x+p) is 1/(x+p)