What is (\partial)/(\partial x)(2xy^2z-4xz^2) ?

The answer to (\partial)/(\partial x)(2xy^2z-4xz^2) is 2y^2z-4z^2

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(\partial)/(\partial x)(2xy^2z-4xz^2)

\frac{\partial}{\partial x} (2 x y^{2} z - 4 x z^{2})

2 y^{2} z - 4 z^{2}

Solution steps

\frac{\partial}{\partial x} (2 x y^{2} z - 4 x z^{2})

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x y^{2} z) - \frac{\partial}{\partial x} (4 x z^{2})

\frac{\partial}{\partial x} (2 x y^{2} z) = 2 y^{2} z

\frac{\partial}{\partial x} (4 x z^{2}) = 4 z^{2}

= 2 y^{2} z - 4 z^{2}

y = \frac{3 ( x - 1 )}{4 x x}

\int x sin (\frac{nπ x}{10}) d x

f (t) = t^{9} - 1

\frac{\partial}{\partial y} (9 x^{6 y})

\frac{\partial}{\partial x} (2 x cos (x^{2} + y^{2}))

What is (\partial)/(\partial x)(2xy^2z-4xz^2) ?
The answer to (\partial)/(\partial x)(2xy^2z-4xz^2) is 2y^2z-4z^2