What is the derivative of f(t)=t^9-1 ?

The derivative of f(t)=t^9-1 is 9t^8

What is the first derivative of f(t)=t^9-1 ?

The first derivative of f(t)=t^9-1 is 9t^8

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derivative of

f (t) = t^{9} - 1

9 t^{8}

Solution steps

\frac{d}{d t} (t^{9} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (t^{9}) - \frac{d}{d t} (1)

\frac{d}{d t} (t^{9}) = 9 t^{8}

\frac{d}{d t} (1) = 0

= 9 t^{8} - 0

Simplify

= 9 t^{8}

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What is the derivative of f(t)=t^9-1 ?
The derivative of f(t)=t^9-1 is 9t^8
What is the first derivative of f(t)=t^9-1 ?
The first derivative of f(t)=t^9-1 is 9t^8