What is the limit as x approaches 0 of ((1+x)/x)^2-1 ?

The limit as x approaches 0 of ((1+x)/x)^2-1 is infinity

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limit as x approaches 0 of ((1+x)/x)^2-1

x \to 0 lim ((\frac{1 + x}{x})^{2} - 1)

\infty

Solution steps

x \to 0 lim ((\frac{1 + x}{x})^{2} - 1)

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 0 - lim ((\frac{1 + x}{x})^{2} - 1) = \infty

x \to 0 + lim ((\frac{1 + x}{x})^{2} - 1) = \infty

= \infty

x \to \infty lim (\frac{x}{θ})

x \to 1 lim (\frac{x ^{2} + 2}{x - 1})

x \to - 2 lim (3 x - 7)

x \to 0 lim (\frac{0}{x - e ^{x} + 1})

x \to - 1 - lim (\frac{x ^{3}}{x ^{2} - 1})

What is the limit as x approaches 0 of ((1+x)/x)^2-1 ?
The limit as x approaches 0 of ((1+x)/x)^2-1 is infinity