What is the solution for (dy)/(dt)=yr(1000-y) ?

The solution for (dy)/(dt)=yr(1000-y) is y=(1000)/(e^{-1000rt+c_{1)}+1}

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(dy)/(dt)=yr(1000-y)

\frac{d y}{d t} = yr (1000 - y)

y = \frac{1000}{e ^{- 1000 r t + c_{1}} + 1}

Solution steps

\frac{d y}{d t} = yr (1000 - y)

Solve Bernoulli ODE:

y = \frac{1000}{e ^{- 1000 r t + c_{1}} + 1}

y = \frac{1000}{e ^{- 1000 r t + c_{1}} + 1}

y = sec^{2} (x), y = 8 cos (x), - \frac{π}{3}, \frac{π}{3}

\int_{1}^{\infty} \frac{ln ( x )}{x ^{\frac{3}{2}}} d x

\frac{d}{d x} (1000 (1 + \frac{x}{12})^{60})

f (x) = (1 - x) (x^{2} - 7)^{2}

f (x) = x^{2} - x + 9, at x = 1

What is the solution for (dy)/(dt)=yr(1000-y) ?
The solution for (dy)/(dt)=yr(1000-y) is y=(1000)/(e^{-1000rt+c_{1)}+1}