What is the limit as x approaches 8 of (x^2-1)/(x-1) ?

The limit as x approaches 8 of (x^2-1)/(x-1) is 9

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limit as x approaches 8 of (x^2-1)/(x-1)

x \to 8 lim (\frac{x ^{2} - 1}{x - 1})

9

Solution steps

x \to 8 lim (\frac{x ^{2} - 1}{x - 1})

Plug in the value

x = 8

= \frac{8 ^{2} - 1}{8 - 1}

Simplify

= 9

x \to 0 lim (\frac{3 x + 7}{x})

x \to \infty lim (- ∣ x ∣)

x \to π lim (2 cos (x) + e^{x})

x \to - 3 + lim (\frac{3 + x}{x})

x \to \infty lim (x^{2} + 3 x)

What is the limit as x approaches 8 of (x^2-1)/(x-1) ?
The limit as x approaches 8 of (x^2-1)/(x-1) is 9