What is the solution for (d^2y)/(dx^2)-3(dy)/(dx)+2y=0 ?

The solution for (d^2y)/(dx^2)-3(dy)/(dx)+2y=0 is y=c_{1}e^{2x}+c_{2}e^x

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(d^2y)/(dx^2)-3(dy)/(dx)+2y=0

\frac{d ^{2} y}{d x ^{2}} - 3 \frac{d y}{d x} + 2 y = 0

y = c_{1} e^{2 x} + c_{2} e^{x}

Solution steps

\frac{d ^{2} y}{d x ^{2}} - 3 \frac{d y}{d x} + 2 y = 0

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} e^{x}

y = c_{1} e^{2 x} + c_{2} e^{x}

x^{^{''}} + 9 x = 27, x (0) = 4, x^{^{'}} (0) = 6

\int \frac{1 + x}{x} d x

n = 1 \sum \infty \frac{2 n}{5 n - 4}

\int \frac{x ^{2} - 4}{x ^{6}} d x

y = x^{3} - 3 x^{2} + 25

What is the solution for (d^2y)/(dx^2)-3(dy)/(dx)+2y=0 ?
The solution for (d^2y)/(dx^2)-3(dy)/(dx)+2y=0 is y=c_{1}e^{2x}+c_{2}e^x