What is the limit as x approaches 0 of ((x+64)^{1/3}-4)/x ?

The limit as x approaches 0 of ((x+64)^{1/3}-4)/x is 1/48

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limit as x approaches 0 of ((x+64)^{1/3}-4)/x

x \to 0 lim (\frac{( x + 64 ) ^{\frac{1}{3}} - 4}{x})

\frac{1}{48}

Decimal Notation

0.02083 \dots

Solution steps

x \to 0 lim (\frac{( x + 64 ) ^{\frac{1}{3}} - 4}{x})

Apply L'Hopital's Rule

: x \to 0 lim \frac{\frac{1}{3 ( x + 64 ) ^{\frac{2}{3}}}}{1}

= x \to 0 lim \frac{\frac{1}{3 ( x + 64 ) ^{\frac{2}{3}}}}{1}

Plug in the value

x = 0

= \frac{\frac{1}{3 ( 0 + 64 ) ^{\frac{2}{3}}}}{1}

Simplify

\frac{\frac{1}{3 ( 0 + 64 ) ^{\frac{2}{3}}}}{1} : \frac{1}{48}

= \frac{1}{48}

\int \frac{1}{( 2 x - 3 ) ^{4}} d x

\int_{1}^{\infty} x^{- \frac{1}{5}} d x

x \to 1 + lim (\frac{x + 1}{x ^{2} - 1})

\int 2 sin (x) + 3 cos (x) d x

y^{^{''}} + y^{^{'}} - 6 y = 0, y (0) = 1, y^{^{'}} (0) = - 13

What is the limit as x approaches 0 of ((x+64)^{1/3}-4)/x ?
The limit as x approaches 0 of ((x+64)^{1/3}-4)/x is 1/48