What is the tangent of x^2+2xy-y^2+x=27,(4,7) ?

The tangent of x^2+2xy-y^2+x=27,(4,7) is y= 23/6 x-25/3

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tangent of x^2+2xy-y^2+x=27,(4,7)

tangent of

x^{2} + 2 x y - y^{2} + x = 27, (4, 7)

y = \frac{23}{6} x - \frac{25}{3}

Solution steps

Find the slope of

x^{2} + 2 x y - y^{2} + x = 27 : \frac{d y}{d x} = \frac{- 2 x - 1 - 2 y}{2 ( x - y )}

Compute the slope of

x^{2} + 2 x y - y^{2} + x = 27

(4, 7) : m = \frac{23}{6}

Find the line with slope m=

\frac{23}{6}

and passing through

(4, 7) : y = \frac{23}{6} x - \frac{25}{3}

y = \frac{23}{6} x - \frac{25}{3}

\frac{d y}{d x} = \frac{y ^{3}}{1 - 2 x y ^{2}}, y (0) = 1

\frac{\partial}{\partial x} (sin (z^{2}) cos (x y))

- cos (θ)

g (x) = (6 x^{4} + 9)^{2} (x^{3} - 4 x)^{3}

\int 7 x^{15} e^{- x^{8}} d x

What is the tangent of x^2+2xy-y^2+x=27,(4,7) ?
The tangent of x^2+2xy-y^2+x=27,(4,7) is y= 23/6 x-25/3