What is the limit as x approaches 1+of 1/(x^2-6x+5) ?

The limit as x approaches 1+of 1/(x^2-6x+5) is -infinity

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limit as x approaches 1+of 1/(x^2-6x+5)

x \to 1 + lim (\frac{1}{x ^{2} - 6 x + 5})

- \infty

Solution steps

x \to 1 + lim (\frac{1}{x ^{2} - 6 x + 5})

For

x

approaching

1

from the right

, x > 1 \Rightarrow x^{2} - 6 x + 5 < 0

The denominator is a negative quantity approaching 0 from the left

= - \infty

t \to - 1 lim (\frac{t + 1}{∣ t + 1 ∣})

x \to 0 lim (\frac{5 x + sin ( x )}{x})

x \to 0 lim (x^{2} + 4 x)

x \to 0 lim (\frac{( 1 - cos ( 4 x ) )}{5 x ^{2}})

x \to 0 lim (x ln (\frac{x}{x + 1}))

What is the limit as x approaches 1+of 1/(x^2-6x+5) ?
The limit as x approaches 1+of 1/(x^2-6x+5) is -infinity