What is the limit as t approaches-1 of (t+1)/(|t+1|) ?

The limit as t approaches-1 of (t+1)/(|t+1|) is diverges

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limit as t approaches-1 of (t+1)/(|t+1|)

t \to - 1 lim (\frac{t + 1}{∣ t + 1 ∣})

diverges

Solution steps

t \to - 1 lim (\frac{t + 1}{∣ t + 1 ∣})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

t \to - 1 + lim (\frac{t + 1}{∣ t + 1 ∣}) = 1

t \to - 1 - lim (\frac{t + 1}{∣ t + 1 ∣}) = - 1

= diverges

x \to 0 lim (\frac{5 x + sin ( x )}{x})

x \to 0 lim (x^{2} + 4 x)

x \to 0 lim (\frac{( 1 - cos ( 4 x ) )}{5 x ^{2}})

x \to 0 lim (x ln (\frac{x}{x + 1}))

x \to 0 lim (\frac{4 x ^{2} - x}{2 x})

What is the limit as t approaches-1 of (t+1)/(|t+1|) ?
The limit as t approaches-1 of (t+1)/(|t+1|) is diverges