What is the solution for (dy)/(dx)=sqrt(x+1) ?

The solution for (dy)/(dx)=sqrt(x+1) is y= 2/3 (x+1)^{3/2}+c_{1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=sqrt(x+1)

\frac{d y}{d x} = x + 1

y = \frac{2}{3} (x + 1)^{\frac{3}{2}} + c_{1}

Solution steps

\frac{d y}{d x} = x + 1

Substitute

\frac{d y}{d x}

with

y^{'} (x)

y^{^{'}} (x) = x + 1

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int x + 1 d x

\int x + 1 d x = \frac{2}{3} (x + 1)^{\frac{3}{2}} + c_{1}

y = \frac{2}{3} (x + 1)^{\frac{3}{2}} + c_{1}

(x + 2 y) d x - x d y = 0

\int (3 x^{4} - 5 x^{2} + x) d x

\int_{\frac{3}{4}}^{\infty} 2 x d x

x \to 1 - lim (\frac{1}{( x - 1 ) ^{2}})

\frac{\partial}{\partial x} (x^{2} - 3 y^{2} - 2)

What is the solution for (dy)/(dx)=sqrt(x+1) ?
The solution for (dy)/(dx)=sqrt(x+1) is y= 2/3 (x+1)^{3/2}+c_{1}