What is the limit as x approaches 0 of [x-2][x+3] ?

The limit as x approaches 0 of [x-2][x+3] is -6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of [x-2][x+3]

x \to 0 lim ([x - 2] [x + 3])

- 6

Solution steps

x \to 0 lim ([x - 2] [x + 3])

Plug in the value

x = 0

= [0 - 2] [0 + 3]

Simplify

= - 6

x \to 1 lim (- (x^{2} - 4 x + 8))

x \to 3 + lim (3 x - 3)

x \to 1 lim (9 - x^{2})

x \to \infty lim (e^{9 x l n (1 + \frac{1}{7 x})})

x \to 0 lim (sin (∣ x ∣))

What is the limit as x approaches 0 of [x-2][x+3] ?
The limit as x approaches 0 of [x-2][x+3] is -6