What is the derivative of x^2+4x ?

The derivative of x^2+4x is 2x+4

What is the first derivative of x^2+4x ?

The first derivative of x^2+4x is 2x+4

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derivative of

x^{2} + 4 x

2 x + 4

Solution steps

\frac{d}{d x} (x^{2} + 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4 x)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

= 2 x + 4

\frac{8}{( 2 s + 1 ) ^{3}}

\frac{\partial}{\partial x} (2 x + 3 y - 4)

f (x) \frac{2}{x}

\frac{x ^{2} - 2 x - 3}{( x - 1 ) ^{2}}

144 y^{^{'''}} + 168 y^{^{''}} + 49 y^{^{'}} = 0