What is the solution for x^{''}+bx=0 ?

The solution for x^{''}+bx=0 is x=c_{1}cos(sqrt(b)t)+c_{2}sin(sqrt(b)t)

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x^{''}+bx=0

x^{^{''}} + b x = 0

x = c_{1} cos (b t) + c_{2} sin (b t)

Solution steps

x^{''} (t) + b x (t) = 0

Solve linear ODE:

x = c_{1} cos (b t) + c_{2} sin (b t)

x = c_{1} cos (b t) + c_{2} sin (b t)

\int (2 x^{2} + 3 x + 7) d x

y = x^{2} - 3, (- 1, - 2)

f (x) = 7 x^{3} e^{- x}

\int \frac{1}{y ^{\frac{1}{2}}} d y

\int e^{2 x} sin (e^{2 x}) d x

What is the solution for x^{''}+bx=0 ?
The solution for x^{''}+bx=0 is x=c_{1}cos(sqrt(b)t)+c_{2}sin(sqrt(b)t)