What is the limit as x approaches 0 of (x^2+x+1)/x ?

The limit as x approaches 0 of (x^2+x+1)/x is diverges

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limit as x approaches 0 of (x^2+x+1)/x

x \to 0 lim (\frac{x ^{2} + x + 1}{x})

diverges

Solution steps

x \to 0 lim (\frac{x ^{2} + x + 1}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{x ^{2} + x + 1}{x}) = \infty

x \to 0 - lim (\frac{x ^{2} + x + 1}{x}) = - \infty

= diverges

x \to 1 lim (\frac{e ^{x}}{x ^{2}})

x \to 4 lim (5 x^{2} - 9 x - 3)

x \to 0 + lim (- 4 ln (x))

x \to 0 + lim (x^{18 x})

x \to 0 lim (e^{- x} - 1)

What is the limit as x approaches 0 of (x^2+x+1)/x ?
The limit as x approaches 0 of (x^2+x+1)/x is diverges