What is the limit as x approaches 0+of (ln^2(x))/2 ?

The limit as x approaches 0+of (ln^2(x))/2 is infinity

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limit as x approaches 0+of (ln^2(x))/2

x \to 0 + lim (\frac{ln ^{2} ( x )}{2})

\infty

Solution steps

x \to 0 + lim (\frac{ln ^{2} ( x )}{2})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= \frac{1}{2} \cdot x \to 0 + lim (ln^{2} (x))

x \to a lim [f (x)]^{b} = [x \to a lim f (x)]^{b}

With the exception of indeterminate form

= \frac{1}{2} (x \to 0 + lim (ln (x)))^{2}

Apply the common limit:

x \to 0 + lim (ln (x)) = - \infty

= \frac{1}{2} (- \infty)^{2}

Simplify

\frac{1}{2} (- \infty)^{2} : \infty

= \infty

\frac{\partial}{\partial y} (x^{2} + \frac{x}{y})

\int x^{11} x^{6} + 6 d x

2 x^{2} - 3 x + 4

x \to 1 lim (\frac{x - 2}{x - 1})

x \to 0 + lim (ln (x) tan (x))

What is the limit as x approaches 0+of (ln^2(x))/2 ?
The limit as x approaches 0+of (ln^2(x))/2 is infinity