What is laplacetransform t-4 ?

The answer to laplacetransform t-4 is 1/(s^2)-4/s

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

laplacetransform t-4

laplace transform

t - 4

\frac{1}{s ^{2}} - \frac{4}{s}

Solution steps

L {t - 4}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {t} - L {4}

L {t} : \frac{1}{s ^{2}}

L {4} : \frac{4}{s}

= \frac{1}{s ^{2}} - \frac{4}{s}

f (x) = \frac{7}{x , at ( 4 , \frac{7}{2} )}

f (x) = - x^{3}

x^{2} \frac{d y}{d x} + (x^{2} + 2 x) y = e^{x}

x^{2} y^{^{'}} + y^{2} = x y

\frac{d}{d x} ((2 x + 5)^{\frac{1}{3}})

What is laplacetransform t-4 ?
The answer to laplacetransform t-4 is 1/(s^2)-4/s