What is (\partial)/(\partial x)(1+x^2) ?

The answer to (\partial)/(\partial x)(1+x^2) is 2x

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(\partial)/(\partial x)(1+x^2)

\frac{\partial}{\partial x} (1 + x^{2})

2 x

Solution steps

\frac{\partial}{\partial x} (1 + x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (1) + \frac{\partial}{\partial x} (x^{2})

\frac{\partial}{\partial x} (1) = 0

\frac{\partial}{\partial x} (x^{2}) = 2 x

= 0 + 2 x

Simplify

= 2 x

\int - \frac{cos ( n x )}{n} d x

\int (π t - t^{2}) cos (n t) d t

\int - 3 cos (t) d t

y^{^{''}} - 2 y^{^{'}} + 5 y = 2 cos (2 t) e^{t}

y = \frac{2 x}{3 - cot ( x )}

What is (\partial)/(\partial x)(1+x^2) ?
The answer to (\partial)/(\partial x)(1+x^2) is 2x