What is the integral of-3cos(t) ?

The integral of-3cos(t) is -3sin(t)+C

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integral of-3cos(t)

\int - 3 cos (t) d t

- 3 sin (t) + C

Solution steps

\int - 3 cos (t) d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 3 \cdot \int cos (t) d t

Use the common integral:

\int cos (t) d t = sin (t)

= - 3 sin (t)

Add a constant to the solution

= - 3 sin (t) + C

y^{^{''}} - 2 y^{^{'}} + 5 y = 2 cos (2 t) e^{t}

y = \frac{2 x}{3 - cot ( x )}

(e)^{^{'}}

\int_{0}^{\infty} \frac{1}{x} d x

x + e^{2 x}