What is the limit as x approaches 4 of 1/(64-x^3) ?

The limit as x approaches 4 of 1/(64-x^3) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 4 of 1/(64-x^3)

x \to 4 lim (\frac{1}{64 - x ^{3}})

diverges

Solution steps

x \to 4 lim (\frac{1}{64 - x ^{3}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 4 + lim (\frac{1}{64 - x ^{3}}) = - \infty

x \to 4 - lim (\frac{1}{64 - x ^{3}}) = \infty

= diverges

x \to 0 lim (\frac{tan ( 5 x )}{sin ( x )})

x \to 0 lim (2 x^{4} - x^{2} - 8 x)

x \to 0 - lim (\frac{1}{1 - x})

x \to 1 lim (5 x + 8)

x \to 3 + lim (\frac{1}{( x - 3 )})

What is the limit as x approaches 4 of 1/(64-x^3) ?
The limit as x approaches 4 of 1/(64-x^3) is diverges