What is the limit as x approaches 1 of x^2+4x-5 ?

The limit as x approaches 1 of x^2+4x-5 is 0

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limit as x approaches 1 of x^2+4x-5

x \to 1 lim (x^{2} + 4 x - 5)

0

Solution steps

x \to 1 lim (x^{2} + 4 x - 5)

Plug in the value

x = 1

= 1^{2} + 4 \cdot 1 - 5

Simplify

= 0

x \to - 1 lim (- \frac{1}{x + 1})

x \to 3 lim (\frac{3 x - 1}{x + 1})

x \to - 2 lim (x - 1)

x \to 0 lim (3 x + 7)

x \to 1 lim (11)

What is the limit as x approaches 1 of x^2+4x-5 ?
The limit as x approaches 1 of x^2+4x-5 is 0